need international travel or cruise leads

Анульовано Опубліковано %project.relative_time Оплачується при отриманні
Анульовано Оплачується при отриманні

I need travel leads and point of origin is fro the following states:

Florida,New York, California, Texas, Oregon, Washington, Nevada, Utah, Georgia, Pennsylvania, Massachusetts, Connecticut, Rhode Island,Maine, Louisiana

I need around 15-20k leads. Due is Friday December 21, 2018.

I need 3-5 samples for each state witin the our for vetting.

INFORMATION NEEDED:

1. TRAVELERS NAME

2. EMAIL (VERIFIED)

3. PHONE (VERIFIED)

***ADITIONAL $$$ IF YOU CAN PROVIDE INFORMATION ABOUT THEIR PAST VACATION DESTINATION/S

Введення даних Data Scraping Growth Hacking

ID Проекту: #18366276

Про проект

6 заявок(-ки) Дистанційний проект Остання активність 5 роки(ів) тому

6 фрілансерів(-и) готові виконати цю роботу у середньому за $1143

polarjin2017

Hello? How are you? I have good experiences in "need international travel or cruise leads" as you can see my profile for these (Data Entry, Data Scraping, Growth Hacking). I have been working for 7 yrs in this scope Більше

$800 USD за 3 дні(-в)
(40 відгуків(и))
5.8
NirmalaSharma1

I have 6 years of rich experience in market research.i have 23000 of first linkedin connections.I have rich data base of decisions makers.

$1111 USD за 5 дні(-в)
(0 відгуків(и))
0.0
semakembot29

I can work full time for this job, I work as a call center agent for about 3 years now, I can type 35 wpm, I can do multi task like what I'm doing in BPO industry. I also have an experience in Travel account, I sell ti Більше

$1250 USD за 20 дні(-в)
(0 відгуків(и))
0.0
shanksss

we can provide the travel database, with the fields of past travellers

$1333 USD за 1 день
(0 відгуків(и))
0.0
Teddata

hi, i am an experienced data scrapper & data miner (though new in this site). I have already scrapped frequent travelers data from 2 sites earlier ( Expedia & 123travel). only 15K records, i can give you in just 2 days Більше

$1250 USD за 3 дні(-в)
(0 відгуків(и))
0.0